1/20(16-x)=-12(x-6)

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Solution for 1/20(16-x)=-12(x-6) equation: 



1/20(16-x)=-12(x-6)

We move all terms to the left:

1/20(16-x)-(-12(x-6))=0



Domain of the equation: 20(16-x)!=0

x∈R



We add all the numbers together, and all the variables

1/20(-1x+16)-(-12(x-6))=0

We multiply all the terms by the denominator


-((-12(x-6)))*20(-1x+16)+1=0



We calculate terms in parentheses: -((-12(x-6)))*20(-1x+16), so:

(-12(x-6)))*20(-1x+16

We add all the numbers together, and all the variables

-1x+(-12(x-6)))*20(+16

Back to the equation:

-(-1x+(-12(x-6)))*20(+16)



We add all the numbers together, and all the variables

-(-1x+(-12(x-6)))*2016+1=0

We move all terms containing x to the left, all other terms to the right

-(-1x+(-12(x-6)))*2016=-1

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