1/20(4p-6)=1/10(p+8)

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Solution for 1/20(4p-6)=1/10(p+8) equation: 



1/20(4p-6)=1/10(p+8)

We move all terms to the left:

1/20(4p-6)-(1/10(p+8))=0



Domain of the equation: 20(4p-6)!=0

p∈R





Domain of the equation: 10(p+8))!=0

p∈R



We calculate fractions


(10pp/(20(4p-6)*10(p+8)))+(-20p4/(20(4p-6)*10(p+8)))=0



We calculate terms in parentheses: +(10pp/(20(4p-6)*10(p+8))), so:

10pp/(20(4p-6)*10(p+8))

We multiply all the terms by the denominator


10pp

Back to the equation:

+(10pp)





We calculate terms in parentheses: +(-20p4/(20(4p-6)*10(p+8))), so:

-20p4/(20(4p-6)*10(p+8))

We multiply all the terms by the denominator


-20p4

We add all the numbers together, and all the variables

-20p^4

We do not support eppression: p^4

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