1/2=9z+3/2z-5

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Solution for 1/2=9z+3/2z-5 equation: 



1/2=9z+3/2z-5

We move all terms to the left:

1/2-(9z+3/2z-5)=0



Domain of the equation: 2z-5)!=0

z∈R



We get rid of parentheses

-9z-3/2z+5+1/2=0

We calculate fractions


-9z+5=0

We move all terms containing z to the left, all other terms to the right

-9z=-5

z=-5/-9

z=5/9

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