1/2BxH+3=104

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Solution for 1/2BxH+3=104 equation:



1/2B+3=104
We move all terms to the left:
1/2B+3-(104)=0
Domain of the equation: 2B!=0
B!=0/2
B!=0
B∈R
We add all the numbers together, and all the variables
1/2B-101=0
We multiply all the terms by the denominator
-101*2B+1=0
Wy multiply elements
-202B+1=0
We move all terms containing B to the left, all other terms to the right
-202B=-1
B=-1/-202
B=1/202

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