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1/2a+11/12a+7/3=7/12
We move all terms to the left:
1/2a+11/12a+7/3-(7/12)=0
Domain of the equation: 2a!=0
a!=0/2
a!=0
a∈R
Domain of the equation: 12a!=0We add all the numbers together, and all the variables
a!=0/12
a!=0
a∈R
1/2a+11/12a+7/3-(+7/12)=0
We get rid of parentheses
1/2a+11/12a+7/3-7/12=0
We calculate fractions
2016a^2/2592a^2+1296a/2592a^2+198a/2592a^2+(-126a)/2592a^2=0
We multiply all the terms by the denominator
2016a^2+1296a+198a+(-126a)=0
We add all the numbers together, and all the variables
2016a^2+1494a+(-126a)=0
We get rid of parentheses
2016a^2+1494a-126a=0
We add all the numbers together, and all the variables
2016a^2+1368a=0
a = 2016; b = 1368; c = 0;
Δ = b2-4ac
Δ = 13682-4·2016·0
Δ = 1871424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1871424}=1368$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1368)-1368}{2*2016}=\frac{-2736}{4032} =-19/28 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1368)+1368}{2*2016}=\frac{0}{4032} =0 $
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