1/2b+4=1/8b=88

Solution for 1/2b+4=1/8b=88 equation:

1/2b+4=1/8b=88

We move all terms to the left:

1/2b+4-(1/8b)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



Domain of the equation: 8b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

1/2b-(+1/8b)+4=0

We get rid of parentheses

1/2b-1/8b+4=0

We calculate fractions


8b/16b^2+(-2b)/16b^2+4=0

We multiply all the terms by the denominator


8b+(-2b)+4*16b^2=0

Wy multiply elements

64b^2+8b+(-2b)=0

We get rid of parentheses

64b^2+8b-2b=0

We add all the numbers together, and all the variables

64b^2+6b=0

a = 64; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·64·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*64}=\frac{-12}{128}
=-3/32
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*64}=\frac{0}{128}
=0
$