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1/2b+4=2(b+2)
We move all terms to the left:
1/2b+4-(2(b+2))=0
Domain of the equation: 2b!=0We multiply all the terms by the denominator
b!=0/2
b!=0
b∈R
-((2(b+2)))*2b+4*2b+1=0
Wy multiply elements
-((2(b+2)))*2b+8b+1=0
We add all the numbers together, and all the variables
8b-((2(b+2)))*2b+1=0
We move all terms containing b to the left, all other terms to the right
8b-((2(b+2)))*2b=-1
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