1/2c+2.6c=4.56

Solution for 1/2c+2.6c=4.56 equation:

1/2c+2.6c=4.56

We move all terms to the left:

1/2c+2.6c-(4.56)=0


Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R


We add all the numbers together, and all the variables

2.6c+1/2c-4.56=0

We multiply all the terms by the denominator


(2.6c)*2c-(4.56)*2c+1=0

We add all the numbers together, and all the variables

(+2.6c)*2c-(4.56)*2c+1=0

We multiply parentheses

4c^2-9.12c+1=0

a = 4; b = -9.12; c = +1;
Δ = b2-4ac
Δ = -9.122-4·4·1
Δ = 67.1744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.12)-\sqrt{67.1744}}{2*4}=\frac{9.12-\sqrt{67.1744}}{8}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.12)+\sqrt{67.1744}}{2*4}=\frac{9.12+\sqrt{67.1744}}{8}
$