1/2c+3/4c=3/2c-2

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Solution for 1/2c+3/4c=3/2c-2 equation: 



1/2c+3/4c=3/2c-2

We move all terms to the left:

1/2c+3/4c-(3/2c-2)=0



Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R





Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R





Domain of the equation: 2c-2)!=0

c∈R



We get rid of parentheses

1/2c+3/4c-3/2c+2=0

We calculate fractions


(-12c+1)/8c^2+6c/8c^2+2=0

We multiply all the terms by the denominator


(-12c+1)+6c+2*8c^2=0

We add all the numbers together, and all the variables

6c+(-12c+1)+2*8c^2=0

Wy multiply elements

16c^2+6c+(-12c+1)=0

We get rid of parentheses

16c^2+6c-12c+1=0

We add all the numbers together, and all the variables

16c^2-6c+1=0

a = 16; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·16·1
Δ = -28
Delta is less than zero, so there is no solution for the equation

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