1/2c=c-8=4

Solution for 1/2c=c-8=4 equation:

1/2c=c-8=4

We move all terms to the left:

1/2c-(c-8)=0


Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R


We get rid of parentheses

1/2c-c+8=0

We multiply all the terms by the denominator


-c*2c+8*2c+1=0

Wy multiply elements

-2c^2+16c+1=0

a = -2; b = 16; c = +1;
Δ = b2-4ac
Δ = 162-4·(-2)·1
Δ = 264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{264}=\sqrt{4*66}=\sqrt{4}*\sqrt{66}=2\sqrt{66}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{66}}{2*-2}=\frac{-16-2\sqrt{66}}{-4}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{66}}{2*-2}=\frac{-16+2\sqrt{66}}{-4}
$