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1/2d-11=d
We move all terms to the left:
1/2d-11-(d)=0
Domain of the equation: 2d!=0We add all the numbers together, and all the variables
d!=0/2
d!=0
d∈R
-1d+1/2d-11=0
We multiply all the terms by the denominator
-1d*2d-11*2d+1=0
Wy multiply elements
-2d^2-22d+1=0
a = -2; b = -22; c = +1;
Δ = b2-4ac
Δ = -222-4·(-2)·1
Δ = 492
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{492}=\sqrt{4*123}=\sqrt{4}*\sqrt{123}=2\sqrt{123}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{123}}{2*-2}=\frac{22-2\sqrt{123}}{-4} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{123}}{2*-2}=\frac{22+2\sqrt{123}}{-4} $
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