1/2f+1/4f=3

Solution for 1/2f+1/4f=3 equation:

1/2f+1/4f=3

We move all terms to the left:

1/2f+1/4f-(3)=0


Domain of the equation: 2f!=0

f!=0/2

f!=0

f∈R



Domain of the equation: 4f!=0

f!=0/4

f!=0

f∈R


We calculate fractions


4f/8f^2+2f/8f^2-3=0

We multiply all the terms by the denominator


4f+2f-3*8f^2=0

We add all the numbers together, and all the variables

6f-3*8f^2=0

Wy multiply elements

-24f^2+6f=0

a = -24; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-24)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-24}=\frac{-12}{-48}
=1/4
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-24}=\frac{0}{-48}
=0
$