1/2f+10=35

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Solution for 1/2f+10=35 equation: 



1/2f+10=35

We move all terms to the left:

1/2f+10-(35)=0



Domain of the equation: 2f!=0

f!=0/2

f!=0

f∈R



We add all the numbers together, and all the variables

1/2f-25=0

We multiply all the terms by the denominator


-25*2f+1=0

Wy multiply elements

-50f+1=0

We move all terms containing f to the left, all other terms to the right

-50f=-1

f=-1/-50

f=1/50

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