1/2f-4=f-6

Solution for 1/2f-4=f-6 equation:

1/2f-4=f-6

We move all terms to the left:

1/2f-4-(f-6)=0


Domain of the equation: 2f!=0

f!=0/2

f!=0

f∈R


We get rid of parentheses

1/2f-f+6-4=0

We multiply all the terms by the denominator


-f*2f+6*2f-4*2f+1=0

Wy multiply elements

-2f^2+12f-8f+1=0

We add all the numbers together, and all the variables

-2f^2+4f+1=0

a = -2; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·(-2)·1
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{6}}{2*-2}=\frac{-4-2\sqrt{6}}{-4}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{6}}{2*-2}=\frac{-4+2\sqrt{6}}{-4}
$