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1/2g+1/3g=5/6
We move all terms to the left:
1/2g+1/3g-(5/6)=0
Domain of the equation: 2g!=0
g!=0/2
g!=0
g∈R
Domain of the equation: 3g!=0We add all the numbers together, and all the variables
g!=0/3
g!=0
g∈R
1/2g+1/3g-(+5/6)=0
We get rid of parentheses
1/2g+1/3g-5/6=0
We calculate fractions
(-90g^2)/216g^2+108g/216g^2+72g/216g^2=0
We multiply all the terms by the denominator
(-90g^2)+108g+72g=0
We add all the numbers together, and all the variables
(-90g^2)+180g=0
We get rid of parentheses
-90g^2+180g=0
a = -90; b = 180; c = 0;
Δ = b2-4ac
Δ = 1802-4·(-90)·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-180}{2*-90}=\frac{-360}{-180} =+2 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+180}{2*-90}=\frac{0}{-180} =0 $
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