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1/2g-9=1/2(g-18)
We move all terms to the left:
1/2g-9-(1/2(g-18))=0
Domain of the equation: 2g!=0
g!=0/2
g!=0
g∈R
Domain of the equation: 2(g-18))!=0We calculate fractions
g∈R
(2gg/(4g^2g+(-(1*2g)/(4g^2g-9=0
We can not solve this equation
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