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h in (-oo:+oo)
(1/3)*(h-6)+(1/2)*h = (5/6)*h+3 // - (5/6)*h+3
(1/3)*(h-6)+(1/2)*h-((5/6)*h)-3 = 0
(1/3)*(h-6)+(1/2)*h+(-5/6)*h-3 = 0
1/3*(h-6)+h/2+(-5*h)/6-3 = 0
(1/3*2*6*(h-6))/(2*6)+(6*h)/(2*6)+(-5*2*h)/(2*6)+(-3*2*6)/(2*6) = 0
1/3*2*6*(h-6)+6*h-5*2*h-3*2*6 = 0
10*h-10*h-36-24 = 0
-36-24 = 0
-60 = 0
-60/(2*6) = 0
-60/(2*6) = 0 // * 2*6
-60 = 0
h belongs to the empty set
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