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h in (-oo:+oo)
(1/3)*(h-7)+(1/2)*h = (5/6)*h+2 // - (5/6)*h+2
(1/3)*(h-7)+(1/2)*h-((5/6)*h)-2 = 0
(1/3)*(h-7)+(1/2)*h+(-5/6)*h-2 = 0
1/3*(h-7)+h/2+(-5*h)/6-2 = 0
(1/3*2*6*(h-7))/(2*6)+(6*h)/(2*6)+(-5*2*h)/(2*6)+(-2*2*6)/(2*6) = 0
1/3*2*6*(h-7)+6*h-5*2*h-2*2*6 = 0
10*h-10*h-28-24 = 0
-28-24 = 0
-52 = 0
-52/(2*6) = 0
-52/(2*6) = 0 // * 2*6
-52 = 0
h belongs to the empty set
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