1/2k-(k+1/3)=1/6(k+1)

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Solution for 1/2k-(k+1/3)=1/6(k+1) equation: 


k in (-oo:+oo)

(1/2)*k-k-(1/3) = (1/6)*(k+1) // - (1/6)*(k+1)

(1/2)*k-((1/6)*(k+1))-k-(1/3) = 0

(-1/6)*(k+1)+(1/2)*k-k-1/3 = 0

k/2-1/6*(k+1)-k-1/3 = 0

(-1/6*2*3*(k+1))/(2*3)+(3*k)/(2*3)+(2*3*(-k))/(2*3)+(-1*2)/(2*3) = 0

3*k-1/6*2*3*(k+1)+2*3*(-k)-1*2 = 0

2*k-6*k-2-1 = 0

-4*k-2-1 = 0

-4*k-3 = 0

(-4*k-3)/(2*3) = 0

(-4*k-3)/(2*3) = 0 // * 2*3

-4*k-3 = 0

-4*k-3 = 0 // + 3

-4*k = 3 // : -4

k = 3/(-4)

k = -3/4

k = -3/4

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