1/2k-(k+1/3)=1/6(k+2)

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Solution for 1/2k-(k+1/3)=1/6(k+2) equation:


k in (-oo:+oo)

(1/2)*k-k-(1/3) = (1/6)*(k+2) // - (1/6)*(k+2)

(1/2)*k-((1/6)*(k+2))-k-(1/3) = 0

(-1/6)*(k+2)+(1/2)*k-k-1/3 = 0

k/2-1/6*(k+2)-k-1/3 = 0

(-1/6*2*3*(k+2))/(2*3)+(3*k)/(2*3)+(2*3*(-k))/(2*3)+(-1*2)/(2*3) = 0

3*k-1/6*2*3*(k+2)+2*3*(-k)-1*2 = 0

2*k-6*k-2-2 = 0

-4*k-2-2 = 0

-4*k-4 = 0

(-4*k-4)/(2*3) = 0

(-4*k-4)/(2*3) = 0 // * 2*3

-4*k-4 = 0

-4*k-4 = 0 // + 4

-4*k = 4 // : -4

k = 4/(-4)

k = -1

k = -1

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