1/2k-(k+1/3)=1/6(k+3)

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Solution for 1/2k-(k+1/3)=1/6(k+3) equation: 



1/2k-(k+1/3)=1/6(k+3)

We move all terms to the left:

1/2k-(k+1/3)-(1/6(k+3))=0



Domain of the equation: 2k!=0

k!=0/2

k!=0

k∈R





Domain of the equation: 6(k+3))!=0

k∈R



We add all the numbers together, and all the variables

1/2k-(+k+1/3)-(1/6(k+3))=0

We get rid of parentheses

1/2k-k-(1/6(k+3))-1/3=0

We calculate fractions


(18kk/(36k^2k+(-(1*2k*3)/(36k^2k+(-72k^2)/(36k^2k-k=0

We can not solve this equation

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