1/2k-(k+1/5)=1/10(k+2)

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Solution for 1/2k-(k+1/5)=1/10(k+2) equation: 



1/2k-(k+1/5)=1/10(k+2)

We move all terms to the left:

1/2k-(k+1/5)-(1/10(k+2))=0



Domain of the equation: 2k!=0

k!=0/2

k!=0

k∈R





Domain of the equation: 10(k+2))!=0

k∈R



We add all the numbers together, and all the variables

1/2k-(+k+1/5)-(1/10(k+2))=0

We get rid of parentheses

1/2k-k-(1/10(k+2))-1/5=0

We calculate fractions


(50kk/(100k^2k+(-(1*2k*5)/(100k^2k+(-20k^2)/(100k^2k-k=0

We can not solve this equation

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