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1/2k-(k+5)=1/10(k+1)
We move all terms to the left:
1/2k-(k+5)-(1/10(k+1))=0
Domain of the equation: 2k!=0
k!=0/2
k!=0
k∈R
Domain of the equation: 10(k+1))!=0We get rid of parentheses
k∈R
1/2k-k-(1/10(k+1))-5=0
We calculate fractions
-k+(10kk/(20k^2k+(-(1*2k)/(20k^2k-5=0
We can not solve this equation
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