1/2ln(y-1)-1/2ln(y+1)=1/2ln(x-1)-1/2ln(x+1)

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Solution for 1/2ln(y-1)-1/2ln(y+1)=1/2ln(x-1)-1/2ln(x+1) equation:


D( x )

y+1 <= 0

y-1 <= 0

x+1 <= 0

x-1 <= 0

y+1 <= 0

y+1 <= 0

y+1 <= 0

x naleu017Cy do R

y-1 <= 0

y-1 <= 0

y-1 <= 0

x naleu017Cy do R

x+1 <= 0

x+1 <= 0

x+1 <= 0 // - 1

x <= -1

x-1 <= 0

x-1 <= 0

x-1 <= 0 // + 1

x <= 1

x belongs to the empty set

(1/2)*ln(y-1)-((1/2)*ln(y+1)) = (1/2)*ln(x-1)-((1/2)*ln(x+1))

x belongs to the empty set

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