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1/2m+3/4m=3
We move all terms to the left:
1/2m+3/4m-(3)=0
Domain of the equation: 2m!=0
m!=0/2
m!=0
m∈R
Domain of the equation: 4m!=0We calculate fractions
m!=0/4
m!=0
m∈R
4m/8m^2+6m/8m^2-3=0
We multiply all the terms by the denominator
4m+6m-3*8m^2=0
We add all the numbers together, and all the variables
10m-3*8m^2=0
Wy multiply elements
-24m^2+10m=0
a = -24; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-24)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-24}=\frac{-20}{-48} =5/12 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-24}=\frac{0}{-48} =0 $
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