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1/2m-2=-2/3m-3
We move all terms to the left:
1/2m-2-(-2/3m-3)=0
Domain of the equation: 2m!=0
m!=0/2
m!=0
m∈R
Domain of the equation: 3m-3)!=0We get rid of parentheses
m∈R
1/2m+2/3m+3-2=0
We calculate fractions
3m/6m^2+4m/6m^2+3-2=0
We add all the numbers together, and all the variables
3m/6m^2+4m/6m^2+1=0
We multiply all the terms by the denominator
3m+4m+1*6m^2=0
We add all the numbers together, and all the variables
7m+1*6m^2=0
Wy multiply elements
6m^2+7m=0
a = 6; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·6·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*6}=\frac{-14}{12} =-1+1/6 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*6}=\frac{0}{12} =0 $
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