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1/2m=12-m
We move all terms to the left:
1/2m-(12-m)=0
Domain of the equation: 2m!=0We add all the numbers together, and all the variables
m!=0/2
m!=0
m∈R
1/2m-(-1m+12)=0
We get rid of parentheses
1/2m+1m-12=0
We multiply all the terms by the denominator
1m*2m-12*2m+1=0
Wy multiply elements
2m^2-24m+1=0
a = 2; b = -24; c = +1;
Δ = b2-4ac
Δ = -242-4·2·1
Δ = 568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{568}=\sqrt{4*142}=\sqrt{4}*\sqrt{142}=2\sqrt{142}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{142}}{2*2}=\frac{24-2\sqrt{142}}{4} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{142}}{2*2}=\frac{24+2\sqrt{142}}{4} $
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