1/2n+16=4+3/4n

Solution for 1/2n+16=4+3/4n equation:

1/2n+16=4+3/4n

We move all terms to the left:

1/2n+16-(4+3/4n)=0


Domain of the equation: 2n!=0

n!=0/2

n!=0

n∈R



Domain of the equation: 4n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

1/2n-(3/4n+4)+16=0

We get rid of parentheses

1/2n-3/4n-4+16=0

We calculate fractions


4n/8n^2+(-6n)/8n^2-4+16=0

We add all the numbers together, and all the variables

4n/8n^2+(-6n)/8n^2+12=0

We multiply all the terms by the denominator


4n+(-6n)+12*8n^2=0

Wy multiply elements

96n^2+4n+(-6n)=0

We get rid of parentheses

96n^2+4n-6n=0

We add all the numbers together, and all the variables

96n^2-2n=0

a = 96; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·96·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*96}=\frac{0}{192}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*96}=\frac{4}{192}
=1/48
$