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1/2n+2=2/3n
We move all terms to the left:
1/2n+2-(2/3n)=0
Domain of the equation: 2n!=0
n!=0/2
n!=0
n∈R
Domain of the equation: 3n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
1/2n-(+2/3n)+2=0
We get rid of parentheses
1/2n-2/3n+2=0
We calculate fractions
3n/6n^2+(-4n)/6n^2+2=0
We multiply all the terms by the denominator
3n+(-4n)+2*6n^2=0
Wy multiply elements
12n^2+3n+(-4n)=0
We get rid of parentheses
12n^2+3n-4n=0
We add all the numbers together, and all the variables
12n^2-1n=0
a = 12; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·12·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*12}=\frac{0}{24} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*12}=\frac{2}{24} =1/12 $
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