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1/2n+3=17-3n
We move all terms to the left:
1/2n+3-(17-3n)=0
Domain of the equation: 2n!=0We add all the numbers together, and all the variables
n!=0/2
n!=0
n∈R
1/2n-(-3n+17)+3=0
We get rid of parentheses
1/2n+3n-17+3=0
We multiply all the terms by the denominator
3n*2n-17*2n+3*2n+1=0
Wy multiply elements
6n^2-34n+6n+1=0
We add all the numbers together, and all the variables
6n^2-28n+1=0
a = 6; b = -28; c = +1;
Δ = b2-4ac
Δ = -282-4·6·1
Δ = 760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{760}=\sqrt{4*190}=\sqrt{4}*\sqrt{190}=2\sqrt{190}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-2\sqrt{190}}{2*6}=\frac{28-2\sqrt{190}}{12} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+2\sqrt{190}}{2*6}=\frac{28+2\sqrt{190}}{12} $
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