1/2n+7=n+12/2

Solution for 1/2n+7=n+12/2 equation:

1/2n+7=n+12/2

We move all terms to the left:

1/2n+7-(n+12/2)=0


Domain of the equation: 2n!=0

n!=0/2

n!=0

n∈R


We add all the numbers together, and all the variables

1/2n-(n+6)+7=0

We get rid of parentheses

1/2n-n-6+7=0

We multiply all the terms by the denominator


-n*2n-6*2n+7*2n+1=0

Wy multiply elements

-2n^2-12n+14n+1=0

We add all the numbers together, and all the variables

-2n^2+2n+1=0

a = -2; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·(-2)·1
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{3}}{2*-2}=\frac{-2-2\sqrt{3}}{-4}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{3}}{2*-2}=\frac{-2+2\sqrt{3}}{-4}
$