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1/2n+n=312
We move all terms to the left:
1/2n+n-(312)=0
Domain of the equation: 2n!=0We add all the numbers together, and all the variables
n!=0/2
n!=0
n∈R
n+1/2n-312=0
We multiply all the terms by the denominator
n*2n-312*2n+1=0
Wy multiply elements
2n^2-624n+1=0
a = 2; b = -624; c = +1;
Δ = b2-4ac
Δ = -6242-4·2·1
Δ = 389368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{389368}=\sqrt{4*97342}=\sqrt{4}*\sqrt{97342}=2\sqrt{97342}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-624)-2\sqrt{97342}}{2*2}=\frac{624-2\sqrt{97342}}{4} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-624)+2\sqrt{97342}}{2*2}=\frac{624+2\sqrt{97342}}{4} $
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