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1/2n-2/3n-3/8=-11/8
We move all terms to the left:
1/2n-2/3n-3/8-(-11/8)=0
Domain of the equation: 2n!=0
n!=0/2
n!=0
n∈R
Domain of the equation: 3n!=0We get rid of parentheses
n!=0/3
n!=0
n∈R
1/2n-2/3n-3/8+11/8=0
We calculate fractions
192n/384n^2+(-256n)/384n^2+(198n^2-3)/384n^2=0
We multiply all the terms by the denominator
192n+(-256n)+(198n^2-3)=0
We get rid of parentheses
198n^2+192n-256n-3=0
We add all the numbers together, and all the variables
198n^2-64n-3=0
a = 198; b = -64; c = -3;
Δ = b2-4ac
Δ = -642-4·198·(-3)
Δ = 6472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6472}=\sqrt{4*1618}=\sqrt{4}*\sqrt{1618}=2\sqrt{1618}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-2\sqrt{1618}}{2*198}=\frac{64-2\sqrt{1618}}{396} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+2\sqrt{1618}}{2*198}=\frac{64+2\sqrt{1618}}{396} $
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