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1/2n-3/4n=3
We move all terms to the left:
1/2n-3/4n-(3)=0
Domain of the equation: 2n!=0
n!=0/2
n!=0
n∈R
Domain of the equation: 4n!=0We calculate fractions
n!=0/4
n!=0
n∈R
4n/8n^2+(-6n)/8n^2-3=0
We multiply all the terms by the denominator
4n+(-6n)-3*8n^2=0
Wy multiply elements
-24n^2+4n+(-6n)=0
We get rid of parentheses
-24n^2+4n-6n=0
We add all the numbers together, and all the variables
-24n^2-2n=0
a = -24; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-24)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-24}=\frac{0}{-48} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-24}=\frac{4}{-48} =-1/12 $
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