1/2n-3=4+2/3n=

Solution for 1/2n-3=4+2/3n= equation:

1/2n-3=4+2/3n=

We move all terms to the left:

1/2n-3-(4+2/3n)=0


Domain of the equation: 2n!=0

n!=0/2

n!=0

n∈R



Domain of the equation: 3n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

1/2n-(2/3n+4)-3=0

We get rid of parentheses

1/2n-2/3n-4-3=0

We calculate fractions


3n/6n^2+(-4n)/6n^2-4-3=0

We add all the numbers together, and all the variables

3n/6n^2+(-4n)/6n^2-7=0

We multiply all the terms by the denominator


3n+(-4n)-7*6n^2=0

Wy multiply elements

-42n^2+3n+(-4n)=0

We get rid of parentheses

-42n^2+3n-4n=0

We add all the numbers together, and all the variables

-42n^2-1n=0

a = -42; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-42)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-42}=\frac{0}{-84}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-42}=\frac{2}{-84}
=-1/42
$