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1/2n-6=1/4n+2
We move all terms to the left:
1/2n-6-(1/4n+2)=0
Domain of the equation: 2n!=0
n!=0/2
n!=0
n∈R
Domain of the equation: 4n+2)!=0We get rid of parentheses
n∈R
1/2n-1/4n-2-6=0
We calculate fractions
4n/8n^2+(-2n)/8n^2-2-6=0
We add all the numbers together, and all the variables
4n/8n^2+(-2n)/8n^2-8=0
We multiply all the terms by the denominator
4n+(-2n)-8*8n^2=0
Wy multiply elements
-64n^2+4n+(-2n)=0
We get rid of parentheses
-64n^2+4n-2n=0
We add all the numbers together, and all the variables
-64n^2+2n=0
a = -64; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-64)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-64}=\frac{-4}{-128} =1/32 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-64}=\frac{0}{-128} =0 $
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