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1/2p+1/5p=2/3
We move all terms to the left:
1/2p+1/5p-(2/3)=0
Domain of the equation: 2p!=0
p!=0/2
p!=0
p∈R
Domain of the equation: 5p!=0We add all the numbers together, and all the variables
p!=0/5
p!=0
p∈R
1/2p+1/5p-(+2/3)=0
We get rid of parentheses
1/2p+1/5p-2/3=0
We calculate fractions
(-100p^2)/90p^2+45p/90p^2+18p/90p^2=0
We multiply all the terms by the denominator
(-100p^2)+45p+18p=0
We add all the numbers together, and all the variables
(-100p^2)+63p=0
We get rid of parentheses
-100p^2+63p=0
a = -100; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·(-100)·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*-100}=\frac{-126}{-200} =63/100 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*-100}=\frac{0}{-200} =0 $
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