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1/2p-6=-p
We move all terms to the left:
1/2p-6-(-p)=0
Domain of the equation: 2p!=0We add all the numbers together, and all the variables
p!=0/2
p!=0
p∈R
1/2p-(-1p)-6=0
We get rid of parentheses
1/2p+1p-6=0
We multiply all the terms by the denominator
1p*2p-6*2p+1=0
Wy multiply elements
2p^2-12p+1=0
a = 2; b = -12; c = +1;
Δ = b2-4ac
Δ = -122-4·2·1
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{34}}{2*2}=\frac{12-2\sqrt{34}}{4} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{34}}{2*2}=\frac{12+2\sqrt{34}}{4} $
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