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1/2p=200-1/3p
We move all terms to the left:
1/2p-(200-1/3p)=0
Domain of the equation: 2p!=0
p!=0/2
p!=0
p∈R
Domain of the equation: 3p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
1/2p-(-1/3p+200)=0
We get rid of parentheses
1/2p+1/3p-200=0
We calculate fractions
3p/6p^2+2p/6p^2-200=0
We multiply all the terms by the denominator
3p+2p-200*6p^2=0
We add all the numbers together, and all the variables
5p-200*6p^2=0
Wy multiply elements
-1200p^2+5p=0
a = -1200; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-1200)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-1200}=\frac{-10}{-2400} =1/240 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-1200}=\frac{0}{-2400} =0 $
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