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1/2q+2(q+5)=4(q+1)+1
We move all terms to the left:
1/2q+2(q+5)-(4(q+1)+1)=0
Domain of the equation: 2q!=0We multiply parentheses
q!=0/2
q!=0
q∈R
1/2q+2q-(4(q+1)+1)+10=0
We multiply all the terms by the denominator
2q*2q-((4(q+1)+1))*2q+10*2q+1=0
Wy multiply elements
4q^2-((4(q+1)+1))*2q+20q+1=0
We add all the numbers together, and all the variables
4q^2+20q-((4(q+1)+1))*2q+1=0
We move all terms containing q to the left, all other terms to the right
4q^2+20q-((4(q+1)+1))*2q=-1
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