1/2q+2(q+5)=4(q+1)+1

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Solution for 1/2q+2(q+5)=4(q+1)+1 equation: 



1/2q+2(q+5)=4(q+1)+1

We move all terms to the left:

1/2q+2(q+5)-(4(q+1)+1)=0



Domain of the equation: 2q!=0

q!=0/2

q!=0

q∈R



We multiply parentheses

1/2q+2q-(4(q+1)+1)+10=0

We multiply all the terms by the denominator


2q*2q-((4(q+1)+1))*2q+10*2q+1=0

Wy multiply elements

4q^2-((4(q+1)+1))*2q+20q+1=0

We add all the numbers together, and all the variables

4q^2+20q-((4(q+1)+1))*2q+1=0

We move all terms containing q to the left, all other terms to the right

4q^2+20q-((4(q+1)+1))*2q=-1

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