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1/2q+2(q+5=-4(q+1)+1
We move all terms to the left:
1/2q+2(q+5-(-4(q+1)+1)=0
Domain of the equation: 2q!=0We multiply all the terms by the denominator
q!=0/2
q!=0
q∈R
(2(q+5-(-4(q+1)+1))*2q+1=0
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