1/2r+2(3/4r-1)1/4r+6

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Solution for 1/2r+2(3/4r-1)1/4r+6 equation: 


r in (-oo:+oo)

r*((2*((3/4)*r-1)^1)/4)+(1/2)*r+6 = 0

r*((2*((3/4)*r-1))/4)+(1/2)*r+6 = 0

(2*r*(3/4*r-1))/4+r/2+6 = 0

(2^2*r*(3/4*r-1))/(2*4)+(4*r)/(2*4)+(2*4*6)/(2*4) = 0

2^2*r*(3/4*r-1)+4*r+2*4*6 = 0

3*r^2+48 = 0

(3*r^2+48)/(2*4) = 0

(3*r^2+48)/(2*4) = 0 // * 2*4

3*r^2+48 = 0

3*r^2 = -48 // : 3

r^2 = -16

r belongs to the empty set

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