1/2r+3/4=3/4(-3r-5)

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Solution for 1/2r+3/4=3/4(-3r-5) equation: 



1/2r+3/4=3/4(-3r-5)

We move all terms to the left:

1/2r+3/4-(3/4(-3r-5))=0



Domain of the equation: 2r!=0

r!=0/2

r!=0

r∈R





Domain of the equation: 4(-3r-5))!=0

r∈R



We calculate fractions


(16r(-)/(32r^2(-)+(-(3*2r)/(32r^2(-)+6r/(32r^2(-)=0



We calculate terms in parentheses: +(16r(-)/(32r^2(-)+(-(3*2r)/(32r^2(-)+6r/(32r^2(-), so:

16r(-)/(32r^2(-)+(-(3*2r)/(32r^2(-)+6r/(32r^2(-

We can not solve this equation

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