1/2r=8;r=16

Solution for 1/2r=8;r=16 equation:

1/2r=8r=16

We move all terms to the left:

1/2r-(8r)=0


Domain of the equation: 2r!=0

r!=0/2

r!=0

r∈R


We add all the numbers together, and all the variables

-8r+1/2r=0

We multiply all the terms by the denominator


-8r*2r+1=0

Wy multiply elements

-16r^2+1=0

a = -16; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-16)·1
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*-16}=\frac{-8}{-32}
=1/4
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*-16}=\frac{8}{-32}
=-1/4
$