1/2w+w=8-3/2w

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Solution for 1/2w+w=8-3/2w equation:



1/2w+w=8-3/2w
We move all terms to the left:
1/2w+w-(8-3/2w)=0
Domain of the equation: 2w!=0
w!=0/2
w!=0
w∈R
Domain of the equation: 2w)!=0
w!=0/1
w!=0
w∈R
We add all the numbers together, and all the variables
1/2w+w-(-3/2w+8)=0
We add all the numbers together, and all the variables
w+1/2w-(-3/2w+8)=0
We get rid of parentheses
w+1/2w+3/2w-8=0
We multiply all the terms by the denominator
w*2w-8*2w+1+3=0
We add all the numbers together, and all the variables
w*2w-8*2w+4=0
Wy multiply elements
2w^2-16w+4=0
a = 2; b = -16; c = +4;
Δ = b2-4ac
Δ = -162-4·2·4
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{14}}{2*2}=\frac{16-4\sqrt{14}}{4} $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{14}}{2*2}=\frac{16+4\sqrt{14}}{4} $

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