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1/2x(x+3)=1/3x(8x-10)
We move all terms to the left:
1/2x(x+3)-(1/3x(8x-10))=0
Domain of the equation: 2x(x+3)!=0
x∈R
Domain of the equation: 3x(8x-10))!=0We calculate fractions
x∈R
(3x8/(2x(x+3)*3x(8x-10)))+(-2xx/(2x(x+3)*3x(8x-10)))=0
We calculate terms in parentheses: +(3x8/(2x(x+3)*3x(8x-10))), so:
3x8/(2x(x+3)*3x(8x-10))
We multiply all the terms by the denominator
3x8
We add all the numbers together, and all the variables
3x^8
We do not support expression: x^8
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