1/2x+1/2x+x+x=160

Solution for 1/2x+1/2x+x+x=160 equation:

1/2x+1/2x+x+x=160

We move all terms to the left:

1/2x+1/2x+x+x-(160)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

2x+1/2x+1/2x-160=0

We multiply all the terms by the denominator


2x*2x-160*2x+1+1=0

We add all the numbers together, and all the variables

2x*2x-160*2x+2=0

Wy multiply elements

4x^2-320x+2=0

a = 4; b = -320; c = +2;
Δ = b2-4ac
Δ = -3202-4·4·2
Δ = 102368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{102368}=\sqrt{16*6398}=\sqrt{16}*\sqrt{6398}=4\sqrt{6398}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-4\sqrt{6398}}{2*4}=\frac{320-4\sqrt{6398}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+4\sqrt{6398}}{2*4}=\frac{320+4\sqrt{6398}}{8}
$