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1/2x+1/3x=1/4
We move all terms to the left:
1/2x+1/3x-(1/4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/2x+1/3x-(+1/4)=0
We get rid of parentheses
1/2x+1/3x-1/4=0
We calculate fractions
(-18x^2)/96x^2+48x/96x^2+32x/96x^2=0
We multiply all the terms by the denominator
(-18x^2)+48x+32x=0
We add all the numbers together, and all the variables
(-18x^2)+80x=0
We get rid of parentheses
-18x^2+80x=0
a = -18; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·(-18)·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*-18}=\frac{-160}{-36} =4+4/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*-18}=\frac{0}{-36} =0 $
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