1/2x+1/3y=-1/6;1/2x+2y=3/2

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x+3y=14

Solution for 1/2x+1/3y=-1/6;1/2x+2y=3/2 system of equations: 


  • /| (1/2)*x+(1/3)*y-(-1/6) = 0| (1/2)*x+2*y-(3/2) = 0
  • We try to solve the equation: (1/2)*x+(1/3)*y-(-1/6) = 0
  • 1/2*x+1/3*y+1/6 = 0 // - 1/2*x+1/6
  • 1/3*y = -(1/2*x+1/6) // : 1/3
  • y = (-(1/2*x+1/6))/1/3
  • y = -3*(1/2*x+1/6)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (1/2)*x-3*2*(1/2*x+1/6)-(3/2) = 0| y = -3*(1/2*x+1/6)
  • x/2-6*(1/2*x+1/6)-3/2 = 0
  • -5/2*x-3/2-1 = 0
  • -5/2*x-5/2 = 0
  • -5/2*x-5/2 = 0 // + 5/2
  • -5/2*x = 5/2 // : -5/2
  • x = 5/2/(-5/2)
  • x = -1
  • We insert the solution into one of the initial equations of our system of equations
  • For y = -3*(1/2*x+1/6): 
  • y = -3*(1/6-1*1/2)
  • y = -3*(1/6-1/2)
  • y = -3*(-1/3)
  • y = 1/3*3
  • y = 1
  • We get a system of equations:
  • /| y = 1| x = -1

 

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