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1/2x+1/4-3/8x=1/2
We move all terms to the left:
1/2x+1/4-3/8x-(1/2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
1/2x-3/8x+1/4-(+1/2)=0
We get rid of parentheses
1/2x-3/8x+1/4-1/2=0
We calculate fractions
256x^2/512x^2+128x/512x^2+(-192x)/512x^2+(-128x)/512x^2=0
We multiply all the terms by the denominator
256x^2+128x+(-192x)+(-128x)=0
We get rid of parentheses
256x^2+128x-192x-128x=0
We add all the numbers together, and all the variables
256x^2-192x=0
a = 256; b = -192; c = 0;
Δ = b2-4ac
Δ = -1922-4·256·0
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36864}=192$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-192)-192}{2*256}=\frac{0}{512} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-192)+192}{2*256}=\frac{384}{512} =3/4 $
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